我在EF Core 1.1.2中有一个查询,在客户端进行评估,并想知道是否有更好的方法将其转换为sql?
查询:
from l in _ctx.Locations
join i in _ctx.Inventories on l.Id equals i.LocationId
join it in _ctx.Items on i.ItemId equals it.Id
where l.ProjectId == projectid
group i by new {l.Id, l.LHA} into il
select new InventoryLocations() {
Id= il.Key.Id,
LHA = il.Key.LHA,
FlaggedItems = il.Any(x=>x.Item != null && x.Item.Flagged)
}
如果没有,我还有其他选择吗?
楷模:
public class Location
{
public Guid Id { get; set; }
[ForeignKey("Project")]
public Guid ProjectId { get; set; }
public Project Project {get; set; }
public string Name { get; set; }
public string LHA { get; set; }
[ForeignKey("ScanUser")]
public Guid? ScanUserId { get; set; }
public User ScanUser { get; set; }
[ForeignKey("CheckUser")]
public Guid? CheckUserId { get; set; }
public User CheckUser { get; set; }
[ForeignKey("GroupLeader")]
public Guid? GroupLeaderId { get; set; }
public User GroupLeader { get; set; }
public int State { get; set; }
}
public class Inventory
{
public Guid Id { get; set; }
[ForeignKey("Project")]
public Guid ProjectId { get; set; }
public Project Project {get; set; }
public string EANCode { get; set; }
[ForeignKey("Location")]
public Guid LocationId { get; set; }
public Location Location { get; set; }
public Double ScanQty { get; set; }
[ForeignKey("ScanUser")]
public Guid? ScanUserId { get; set; }
public User ScanUser { get; set; }
public DateTime? ScanDate { get; set; }
[ForeignKey("Item")]
public Guid? ItemId { get; set; }
public Item Item { get; set; }
[ForeignKey("InventoryTask")]
public Guid? InventoryTaskId { get; set; }
public InventoryTask InventoryTask { get; set; }
[ForeignKey("CheckUser")]
public Guid? CheckUserId { get; set; }
public User CheckUser { get; set; }
public DateTime? CheckDate { get; set; }
public Double PrevQty { get; set; }
}
public class Item
{
public Guid Id { get; set; }
[ForeignKey("Project")]
public Guid ProjectId { get; set; }
public Project Project {get; set; }
public string ItemNo { get; set; }
public string EANCode { get; set; }
public string Name { get; set; }
public Double Price { get; set; }
public bool Deleted { get; set; }
public DateTime ChangeTime { get; set; }
public Double BaseQty { get; set; }
public bool Flagged { get; set; }
}
当前(并且在传入的EF Core v.2.0中也看起来如此) GroupBy
查询在本地处理,因此关键是尽可能避免它们。
并且您的查询似乎符合条件 - 无需首先将数据集与连接相乘,然后将其分组。
我注意到你在实体中只使用了引用导航属性和FK,基本上就像数据库表记录和SQL。但EF允许您定义相应的集合导航属性,允许您从逻辑根开始查询,从而消除了连接和分组的需要。
如果您定义从Location
到Inventory
导航属性
public class Location
{
// ...
public ICollection<Inventory> Inventories { get; set; }
}
那么等价的查询可以简单地说:
from loc in _ctx.Locations
where loc.ProjectId == projectid
select new InventoryLocations()
{
Id = loc.Id,
LHA = loc.LHA,
FlaggedItems = loc.Inventories.Any(inv => inv.Item != null && inv.Item.Flagged)
}
这将完全转换为SQL。
如果由于某种原因您无法创建上述集合导航属性,您仍然可以从位置开始并手动将它们与库存相关联:
from loc in _ctx.Locations
where loc.ProjectId == projectid
select new InventoryLocations()
{
Id = loc.Id,
LHA = loc.LHA,
FlaggedItems = _ctx.Inventories.Any(inv => loc.Id == inv.LocationId && inv.Item != null && inv.Item.Flagged)
}
如果您添加导航属性,正如Ivan正确建议:
public class Location
{
// ...
public ICollection<Inventory> Inventories { get; set; }
}
然后你可以简单地创建一个这样的查询:
var locations = _ctx.Locations
.Include(x => x.Inventories)
.ThenInclude(x => x.Item)
.Where(x => x.ProjectId == projectId)
.Select(loc => new InventoryLocations
{
Id = loc.Id,
LHA = loc.LHA,
FlaggedItems = loc.Inventories.Any(inv => inv.LocationId == loc.Id && inv.Item?.Flagged)
});